A body of c = 0.2 kcal/kg degree C is heated through 100 degree C. Percentage increase in mass?
Answer (1)
31st Mar, 2019
Amt. of heat absorbed by the body E= mc T
= m x 0.2 x 100 x 100 = 100 m kcal
Gain in mass = m = E/c^2
=(20m x 4.2 x 10^3)/(3 x 10^8)^2
So, percentage increase in mass = m/m x 100%
=(20m x 4.2 x 10^3) x 100 %/(3 x 10^8)^2 x m
= 9.3 x 10^ -11 %
So percentage increase in mass is 9.3 x 10^ -11 %.
= m x 0.2 x 100 x 100 = 100 m kcal
Gain in mass = m = E/c^2
=(20m x 4.2 x 10^3)/(3 x 10^8)^2
So, percentage increase in mass = m/m x 100%
=(20m x 4.2 x 10^3) x 100 %/(3 x 10^8)^2 x m
= 9.3 x 10^ -11 %
So percentage increase in mass is 9.3 x 10^ -11 %.
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