Two uniform rods A and B of same diameter having length 2 metre and three metre and having mass per unit 4 kg per metre and 6 kg per metre r
Answer (1)
Student Expert
23rd May, 2019
Dear Saiprasad,
Taking m1 and m2 as mass of first and second rod respectively.
m1=4×2= 8kg (m = lamda × lenght)
m2=6×3=18kg
Where lamda is linear density.
Now lets say the interface is our reference which is assumed to be (0,0)
Therefore, the coordinates and Centre of two rods is (-1,0) and (1.5,0) respectively.
Using the formula of Centre of mass -
r = (m1×r1 + m2×r2) /(m1+m2)
=>( 8×(-1) + 18×(1.5))/22
=> 19/22 =0.8636
Hope this helps :)
Taking m1 and m2 as mass of first and second rod respectively.
m1=4×2= 8kg (m = lamda × lenght)
m2=6×3=18kg
Where lamda is linear density.
Now lets say the interface is our reference which is assumed to be (0,0)
Therefore, the coordinates and Centre of two rods is (-1,0) and (1.5,0) respectively.
Using the formula of Centre of mass -
r = (m1×r1 + m2×r2) /(m1+m2)
=>( 8×(-1) + 18×(1.5))/22
=> 19/22 =0.8636
Hope this helps :)
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