A car moves in a circle at the constant speed of 50m/s and complete one revolution in 40s.Determine the magnitude of acceleration of the car
Hello Padmakar!
We know that, distance = speed*time
So, d = 50*40 = 2000m
d = 2*3.14*r (circumference of the circle)
=> 2000=2*3.14*r
On calculating, r = 318.47 m
In this case, required acceleration will be centripetal acceleration.
So, a = (v*v)/r
a = (50*50)/318.47
a = 7.85m/s^2
Hope this helps.
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