Question : A certain number of men completed a piece of work in 60 days. If there were 8 men more, the work could be finished in 10 days less. The number of men originally was:
Option 1: 36
Option 2: 40
Option 3: 30
Option 4: 32
Correct Answer: 40
Solution :
Given:
Let the original no of men be $x$.
$x$ men can finish it in 60 days,
and $(x+8)$ men can finish in 50 days.
$M_{1}D_{1}=M_{2}D_{2}$, where $M_1$ and $M_2$ are men and $D_1$ and $D_2$ are days.
$⇒60x = 50(x+8)$
$⇒10x= 400$
$\therefore x =40$
So, there were 40 men originally.
Hence, the correct answer is 40.
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