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Given that a charge q is placed at the center C of line joining two equal charges Q each,at points A and B.
Let AB=2a
If the net force on each charge will be 0(zero) ,then the system will be in equilibrium.
let the charge Q is present at A.
At equilibrium state ,the total force on this charge is given by
1/4π e0*qQ/a^2 + 1/4π e0*qQ/2a^2 =0
=1/4π e0*qQ/a^2 = - 1/4π e0*qQ/2a^2
on solving we get,
q=-Q/4
Hope it helps!!!!
Thank you!!!!
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