A convex lens is put 10 cm from a light source and it makes a sharp image on a screen, kept 10 cm from the lens. Now a glass block (refractive index 1.5) of 1.5 cm thickness is placed in contact with the light source. To get the sharp image again, the screen is shifted by a distance d. Then
Answer (1)
13th Jun, 2020
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Refraction through parallel slab = s=t(1-1/ μ )
s= shifting of object from slab
t=thickness of slab
μ =Refractive index of slab
F=10/2=5
Due to glass plate shift
s=t
(1-1/ μ )
=1.5
(1-2/3)
=0.5
New u=9.5cm
Using lens formula
1/v=1/f+1/u
1/v=1/5+1/-9.5
1/v=4.5/9.5*5
v=10.55cm
therefore,Shift is 0.55 cm away from the lens.
Hope it helps!!!!
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