A copper atom has 29 electrons revolving around the nucleus. A copper ball contains 4*10^23 atoms. What fraction of the electrons be removed to give the ball a of +9.6uc
Answer (1)
17th Dec, 2019
Hello!
Given,
The charge of each atom is = 29 C
Total charge = 29 x 4 x 10 = 1160 C
Total Number of electrons in Cu = 1160
Then, total number of electrons in 9.6 C = 9 . 6 / 1.6 x 10 ^ -19 = 6 x 10 ^ 19
Therefore, required fraction of electrons removed =
6 x 10 ^ 19 / 1160 = 5 . 17 x 10 ^ 16.
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