A copper disc of radius 0.1 M is rotating about its nature at least Axis with 10 RPS in a uniform magnetic field of 0.1 PVT is trained perpendicular to the field the EMF induced across the radius of the disc is
HIi,
The answer for this question will be π/10.
For solving this you can use the formula Ein = 1/2BwR^2
where Ein denotes induced emf, B is the magnetic field, w(omega) denotes angular frequency of disc and R is the radius of disc.
Here, B = 0.1, R = 0.1 and
w(omega) = 10rps = 20 pi radian/sec.
Therefore, Ein = 1/2 × 0.1 × 20π × (0.1)²
= 1/2 × 20π × 0.01 = π/10 V
Hope this helps.