Question : A dealer sells two machines at the rate of Rs. 15000 per machine. On one he earns a profit of 20 percent and on the other, he loses 40 percent. What is his profit/loss percentage in the whole transaction?
Option 1: 20 percent loss
Option 2: 10 percent loss
Option 3: 10 percent profit
Option 4: 20 percent profit
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Correct Answer: 20 percent loss
Solution : Let the cost price of one machine be Rs. $y$ and the other be Rs. $z$. Cost price of 1st machine: ⇒ $y \times (1 + \frac{20}{100}) = 15000$ ⇒ $y = \frac{15000}{1.2}$ ⇒ $y$ = Rs. 12500 Cost price of 2nd machine: ⇒ $z \times (1 – \frac{40}{100}) = 15000$ ⇒ $z = \frac{15000}{0.6}$ ⇒ $z$ = 25000 ⇒ Total cost price = 12500 + 25000 = Rs. 37500 ⇒ Total selling price = 15000 + 15000 = Rs. 30000 ⇒ Loss = 37500 – 30000 = Rs. 7500 $\therefore$ Loss percentage = 7500 $\times \frac{100}{37500}$ = 20% Hence, the correct answer is a 20 percent loss.
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