A disc rotates horizontally at the rate of 100 rpm MI of disc about an axis of rotation is 1 kg square metre. A plump of molten wax weighing 50 g drops gently at a distance of 20 cm, from the axis of rotation and remains stuck to it. Then increase in MI of the system is
Hello student!
The moment of Inertia of the disc = 1 kg/m^2
The moment of inertia of wax =MR^2 =(50/1000)* (20/100)^2 =0.002 kg/m^2
Increase in Moment if inertia= Moment of inertia of wax =0.002 kg/m^2
Hence, the change in inertia is calculated as 0.002 kg/m^2.
Hope this solution cleared your doubt!