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a hollow spherical shell at outer radius R floats just submerged under the water surface. the inner radius of the shell is r.if the specific gravity of the shell material is 27/8 w.r.t water,the value of r is;


shoitrajput999 8th Sep, 2020
Answer (1)
JAYA KARTHIKA RS 12th Sep, 2020

Hello,

Solution for your question is:

4/3 π (R^3- r^3)ρmg   = 4/3 π R ^3 ρwg

1- (r/ R) ^3 =8 / 27

r /R  =( 19/27)^1/3= 19^1/3 /3

=0.88 =8/9

Hope it helps

Feel free to ask if you have  any questions

Good luck!


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