Question : A is 40% more efficient than B. How much time will both, working together, take to finish the work, which B alone can finish in 36 days?
Option 1: $18$ days
Option 2: $9 \frac{1}{3}$ days
Option 3: $15$ days
Option 4: $11 \frac{2}{3}$ days
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Correct Answer: $15$ days
Solution :
Let the efficiency of B be $10a$.
So, efficiency of A = $10a \times 140\%=14a$
So, total work = $10a\times 36=360a$
Now, if they both work then time required = $\frac{360a}{14a + 10a} = \frac{360a}{24a}=\frac{360}{24} = 15$ days
Hence, the correct answer is 15 days.
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