A liquid enters a tube of variable cross section with velocity 3 Ms-1 through the wider end and leaves from the narrower end whose radius is half of the wider one . The velocity with which it leaves the tube is
Answer (1)
2nd Dec, 2019
Hello Spandana,
Use the princple of Continuity, i.e. A*V=constant, i.e. product of Area of Cross section of tube and velocity with which liquid flows is constant.
Applying relation A*V=A'*V', where A,V are initial area and velocity, and A',V' are final area and velocity respectively, you should get
velocity as 12m/s
Hope this Helps
Regards
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