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A liquid enters a tube of variable cross section with velocity 3 Ms-1 through the wider end and leaves from the narrower end whose radius is half of the wider one . The velocity with which it leaves the tube is


Spandana 2nd Dec, 2019
Answer (1)
sarthak goel 2nd Dec, 2019

Hello Spandana,

Use the princple of Continuity, i.e. A*V=constant, i.e. product of  Area of Cross section of tube and velocity with which liquid flows is constant.

Applying relation A*V=A'*V', where A,V are initial area and velocity, and A',V' are final area and velocity respectively, you should get

velocity as 12m/s

Hope this Helps

Regards

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