#IT
187 Views

a loop of radius r is made from a wire of length l. The magnetic field at the center of the loop is B if the another loop is made from the same wire with n turns what is magnetic field of the new loop at it's center?


Saksham 22nd Dec, 2019
Answer (1)
Avishek Dutta 22nd Dec, 2019
The magnetic field of a loop at its centre be B.
And the radius of the loop be R.
And the no of turns be n.
Now B is directly proportional to n
And B is inversely proportional to R.
Hence B1=B=k/rhence k=Br
Where k is proportionality constant.
n=1 R=r
Now the wire has n turns hence if the radius is r1 then total length is 2pi *r1*n and it's equal to 2pi*r
Hence r1=r/n
Then B2=kn/r1=Br *n/(r/n)=Bn^2.

Related Questions

MAHE Manipal M.Tech 2025
Apply
NAAC A++ Accredited | Accorded institution of Eminence by Govt. of India | NIRF Rank #4
Amity University, Noida Law A...
Apply
700+ Campus placements at top national and global law firms, corporates, and judiciaries
Amity University Noida B.Tech...
Apply
Among Top 30 National Universities for Engineering (NIRF 2024) | 30+ Specializations | AI Powered Learning & State-of-the-Art Facilities
Amity University, Noida BBA A...
Apply
Ranked amongst top 3% universities globally (QS Rankings)
UPES | BBA Admissions 2025
Apply
#41 in NIRF, NAAC ‘A’ Grade | 100% Placement, up to 30% meritorious scholarships
UPES B.Tech Admissions 2025
Apply
Ranked #42 among Engineering colleges in India by NIRF | Highest CTC 50 LPA , 100% Placements
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books