a mild steel specimen of 16 mm diameter shown an elongation of .08mm over a gauge length 80mm calculated the max shear stress in the material assume E =200gpa
Answer (1)
26th Dec, 2019
Hello,
Given that,
diameter = d = 16 mm
elongation = dL = 0.08 mm
Modulus of Elasticity = 200 GPa = 200 x 10^3 N / mm^2
Gauge Length = Length of specimen used for test = L = 80 mm
We know that,
E = stress / strain
So, E = stress / ( dL / L )
So, 200 x 10^3 = stress / ( 0.08 / 80 )
So, stress = 200 N / mm^2
Hence, the maximum stress in the material is 200 N / mm^2
Best Wishes.
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