a parallel plate capacitor of plate area a and separation d is bring charged by AC source so that the displacement current inside the capacitor is the same current carrying the capacitor
Hello candidate,
A parallel plate capacitor of plate area a, the distance between the two plates is considered to be D, show the value of capacitance is equal to €×Area/ Plate Distance.
Now, when the capacitor is brought near a charged AC source then a negative direction of current starts flowing between the plates of the capacitor which is known as induced current because of induction between the AC source and the capacitor.
Hope It was informational!!