A rectangular block of dimensions 6m×4m×2m and density 1.5gm/C.C is lying on horizontal ground with the face of largest area in contact with the ground .the work done in arranging it with its smallest area in contact with the ground is,
Hi,
A rectangular block of dimensions 6m×4m×2m and density 1.5gm/cc is lying on horizontal ground with the face of largest area in contact with the ground.
The volume of block is 6*2*4=48 cu.m.
The density is 1.5 gm/cc.
So the mass is : 1.5*48*1000 kg
Here the work done is in the form of potential eneegy :
So, work done is mgh = 1.5*48*1000*10*2(smallest are in contact)
=1440 kJ.
Hope this helps!