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A solution is prepared by adding 6g of glucose in 18g of water. The mass percent of solute in solution will be a).75% b ).25% c ).33.33% d).50%


nafeesahmad0616 28th Jan, 2021
Answer (1)
ginnisachdeva02_9364270 Student Expert 28th Jan, 2021

Hey!

As we know,

Mass percent of solute = (mass of solute/mass of solution) * 100

Given: Mass of solute (glucose) = 6 g

Mass of solvent (water) = 18 g

Mass of solution (glucose + water) = 6 + 18 = 24g

Therefore, Mass  percent of solute = (6/18)*100

which is , (1/3)*100

Mass percent of solute = 33.33%

Thankyou

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