a stone that wieghs 2kg is thrown vertically upwards with a kinetic energy of 250 joule how high will the stone go before it returns to the ground ? you may assume all the kinetic energy of the stone is changed into potential energy (1 kg f is equal to 10 Newton)
Answer (1)
21st May, 2020
Hello!!!!
Hope you are doing great!!
Given weight of the stone = 2 kg
kinetic energy = 250J
we know that , kinetic energy = 1/2 mv^2
1/2mv^2 = 250 J
1/2 (2)v^2 = 250
v^2 = 250
In the problem ,, given ,, Kinetic energy = potential energy
1/2mv^2 = mgh
v^2 / 2 = gh
v^2 / 2g = h
h=250/2(9.8)
h=12.755m
Therefore, height = 12.755m
Hope it helps!!!
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