a+b+c=0, then(aa/bc+bb/ca+cc/ab=?

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a+b+c=0, then(aa/bc+bb/ca+cc/ab=?

Mdkafil 21st May, 2018

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Answer (1)

yash raj 28th May, 2018

hello mdkafil

on the L.H.S. take the denominator's LCM being abc as a result the addition numerator would be a^3+b^3+c^3= (a+b+c)....

substituting the value of a+b+c =0 the value of req. result is 0.

hope it helps

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