6 Views

Question : ABCD is a cyclic quadrilateral, AB is the diameter of the circle. If angle $\angle ACD=45^{\circ}$, then what is the value of $\angle BAD$?

Option 1: $90^{\circ}$

Option 2: $45^{\circ}$

Option 3: $135^{\circ}$

Option 4: $35^{\circ}$


Team Careers360 25th Jan, 2024
Answer (1)
Team Careers360 26th Jan, 2024

Correct Answer: $45^{\circ}$


Solution :

Since, an angle subtended by the diameter of a circle at the circumference = $90^{\circ}$
⇒ $\angle$ ACB = $90^{\circ}$
$\angle$ BCD = $\angle$ ACD + $\angle$ ACB = $45^{\circ} + 90^{\circ}=135^{\circ}$
Since the opposite angles of a cyclic quadrilateral are supplementary,
$\angle$ BCD + $\angle$ BAD = $180^{\circ}$
$\therefore \angle$ BAD = $180^{\circ} - 135^{\circ}=45^{\circ}$
Hence, the correct answer is $45^{\circ}$.

How to crack SSC CHSL

Candidates can download this e-book to give a boost to thier preparation.

Download Now

Know More About

Related Questions

TOEFL ® Registrations 2024
Apply
Accepted by more than 11,000 universities in over 150 countries worldwide
Manipal Online M.Com Admissions
Apply
Apply for Online M.Com from Manipal University
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books