An integer is chosen at random from the first 200 positive integers what is the probability that the interger chosen is divisible by 6 or 8?
Answer (1)
5th Mar, 2021
A number divisible by any number must be a multiple of the number itself. So we have to find the number of integers between 1-200 (as per definition set of positive integers excludes 0) which are multiple of 6 and 8.
Number of integers multiple of 6: N(multiples of 6)= 33
Number of integers multiple of 8: N(multiples of 8)= 25
Probability of numbers divisible by 6: P(div by 6)=33/200
Probability of numbers divisible by 8: P(div by 8)=25/200
Thus P(divisible by 6 or 8)= P(div by 6)+P(div by 8) = 58/200
I hope my answer helps. All the very best for your future endeavors!
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