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An iron rod of 0.2 cm2 cross sectional area is subjected to a magnetizing field of 1200 A/m if the susceptibility of iron is 599


Megha 25th Apr, 2019
Answer (1)
dhameerbhatia31_7970609 Student Expert 25th Apr, 2019

Hello Megha,

Given: Magnetizing field = H = 1200 A/m, susceptibility = χ = 599,  μo = 4π x 10-7 Wb/Am.

To Find: permeability = μ = ?, Magnetic flux per unit area = B = ?

Solution:

μ = μo ( 1 + χ)



∴  μ = 4π x 10-7  ( 1 + 599) =  4 x 3.142 x 10-7 x 600 = 7.536 x 10-4 H/m.


Now μ = B/H


∴ B = μ H =  7.536 x 10-4 x 1200 =  0.904 T


Ans: Permeability is  7.536 x 10-4 H/m and magnetic flux per unit area = 0.904 T

Thanku.

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