Dear Pawan,

N2O4 ---------NO2.

Initially N2O4 has conc.= 1, then at equilibrium N2O4 has conc.1-X.

And NO2 has conc. =2x

initially we have taken N2O4 =1

Molar mass =92 .V.D at eq.=24.8 M.w.=60.

n initial/ n final =M final/M initial

1/1-X+2X=60/92

1/1+X=60/92

1+X=92/60

X=92/60 -1

X=32/60

X=0.53

percentage dissociation=0.53 X 100=53

All the best

Hope this helps