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at what temperature 25dm3 of oxygen at 283 k is heated to make its volume 30dm3


preetismita04 17th Oct, 2020
Answers (2)
vishav sarao 28th Aug, 2021

V1=25 dm3          T1=283k

V2=30 dm3          T2=?

According to Charles law


V2/V1 = T2/T1

30/25 = T2/283

T2 = 30×283/25

T2 = 339.6k

Aman Ghatiya 17th Oct, 2020

Hello
preetismita04
, From some research on internet I found that it is not such a difficult solution you can do it easily by the formula of Charles law  which is V1/T1=V2/T2.

And the solution is:

T2=30*283/25
T2=339.6K

Hope you understand it and it will be helpful for you :)

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