92.5 is a very good score, so before answering your question I would like to Congratulate you and with this rank, you will definitely get admission to a good Institution. Your rank can be predicted between 55k-65k as compared to last year ranks in this percentile.

The formula to calculate the NTA score is:

Percentile Score of a Candidate = 100 x (Number of candidates who secured a raw score (or actual score) EQUAL TO OR LESS than the candidate) / (Total number of candidates who appeared in that session).

But as compared to last year closing ranks for the CSE/IT branch is approx 11k and 14k for home state category, so its difficult for you to get admission in NIT Jalanadhar. I suggest you to look forward to other colleges.

Best of luck!!

Hi Manpreet,

According to the formula (100 - your total score) X 869010 /100 your expected rank is coming out to be AIR 65175 and it can vary as the number of students writing the April attempt is expected to increase.

You have not mentioned your category here.

These are the General category cutoffs of 2019 of NIT Jalandar:-

Computer Science and Engineering - AIR 10800

Information Technology - AIR 13479

Cutoffs of 2018:-

Computer Science and Engineering - AIR 6181

Information Technology - AIR 12266

According to the cutoffs mentioned above you do not qualify for getting IT or CSE in NIT Jalandar. You can go for other lower cutoff branches in this college or you may take admission in a state level or private college.

You can appear with full determination for the April Exam to get the preferred branch in your preferred college.

You may refer to this article for more detailed information.

Your one-stop B.Tech Counselling package with Full-Length JEE Main Mock Tests, 15+ College Predictors, a printed Almanac with 1000+ FAQs on Admissions & more

B. Tech Companion

If you require to know colleges for which you are eligible then you should go to the link mentioned below.

Link - JEE Main College Predictor

Hope this information helps you.

Best of Luck!