Diffrentiation of parametric function

Hi,



In a parametric function, there will two equations given for example suppose



y=sin a



x= cos a, where 'a' is the parameter.



So in order to find a parametric equation, you will need to find (dy/dx)



On differentiating y and x with respect to a (since a is the parameter), we get



dy/da= cos a



dx/da= -sin a



So now we will need to find dy/dx in order to find parametric function. So,



dy/dx= (dy/da)÷(dx/da)= (cos a/-sin a)= -cot a



So -cot a is the parametric function of the 2 equation.



Following this process you can solve any parametric function.