Question : Directions: A man is 3 years older than his wife and four times as old as his son. If the son becomes 15 years old after 3 years, then what is the present age of the wife?
Option 1: 60 years
Option 2: 51 years
Option 3: 48 years
Option 4: 45 years
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Correct Answer: 45 years
Solution : Let the man's present age be A, his wife's present age be B, and his son's age be C.
As per the given information,
The man is 3 years older than his wife ⇒ A = B + 3
The man's age is four times the age of his son's age ⇒ A = 4 × C = 4C
After 3 years, the man's son's age = 15 years
Thus, his present age = 15 – 3 = 12 years, i.e., C = 12
If C = 12, then A = 4 × 12 = 48 years
⇒ A = B + 3 ⇒ B = A – 3 = 48 – 3 = 45 years
So, the man's wife's present age is 45 years. Hence, the fourth option is correct.
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