Question : Directions: The age of Dr. Pandey is four times the age of his son. After 10 years, the age of Dr. Pandey will be twice the age of his son. What is the present age of Dr. Pandey's son?
Option 1: 4 years
Option 2: 5 years
Option 3: 6 years
Option 4: 8 years
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Correct Answer: 5 years
Solution : Let Dr. Pandey's present age be A, and Dr. Pandey's son's present age be B.
As per the given information,
Dr. Pandey's age is four times the age of his son ⇒ A = 4 × B = 4B
After 10 years, Dr. Pandey's age = (A + 10), and Dr. Pandey's son's age = (B + 10)
Also, after 10 years, Dr. Pandey's age will be twice his son's age, i.e., (A + 10) = 2 × (B + 10)
As, A = 4B; therefore, (A + 10) = 2 × (B + 10) can be written as –
⇒ (4B + 10) = 2 × (B + 10)
⇒ 4B + 10 = 2B + 20
⇒ 4B – 2B = 20 – 10
⇒ 2B = 10 ⇒ B = 10 ÷ 2
⇒ B = 5
So, Dr. Pandey's son's present age is 5 years. Hence, the second option is correct.
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