Question : Directions: Which two numbers should be interchanged, to make the given equation correct? 192 ÷ 12 × 6 + 16 – 18 = 66
Option 1: 16 and 18
Option 2: 16 and 6
Option 3: 6 and 18
Option 4: 16 and 12
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Correct Answer: 16 and 12
Solution : Given: 192 ÷ 12 × 6 + 16 – 18 = 66
Replace the given numbers in the options one by one with the original numbers in the given equation. First option: 16 and 18 192 ÷ 12 × 6 + 16 – 18 = 66 = 192 ÷ 12 × 6 + 18 – 16 = 66 = 16 × 6 + 18 – 16 = 98 ≠ 66 Second option: 16 and 6 192 ÷ 12 × 6 + 16 – 18 = 66 = 192 ÷ 12 × 16 + 6 – 18 = 66 = 16 × 16 + 6 – 18 = 256 + 6 – 18 = 244 ≠ 66 Third option: 6 and 18 192 ÷ 12 × 6 + 16 – 18 = 66 = 192 ÷ 12 × 18 + 16 – 6 = 66 = 16 × 18 + 16 – 6 = 288 + 16 – 6 = 298 ≠ 66 Fourth Option: 16 and 12 192 ÷ 12 × 6 + 16 – 18 = 66 = 192 ÷ 16 × 6 + 12 – 18 = 66 = 12 × 6 + 12 – 18 = 72 + 12 – 18 = 66
Here, only the fourth option satisfies the R.H.S. of the given equation. Hence, the fourth option is correct.
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