find the centre and radius of the circle 3x2+3y2-2x-1=0
Answer (1)
11th Jul, 2020
By using completing the square method we get the equation
(x-1/3) whole square + y square = (2/3)whole square. The equation of circle is
(x-h) whole square + (y-k) whole square = (r)square.
by this we can say that the center which is in the form (h,k) is (1/3,0) and the radius is (2/3).
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