find the coordinate of a point whose ditance from (3,5) is 5 unit and from (0,1) is 10 unit
Answer (1)
11th Nov, 2020
Hello student!!
Let , P= (3,5) distance is 5 units from Q and
Let R= (0,1) distance is 10 units from Q.
Let the point be Q(x,y)
Let m and n divide the point in the ratio 5:10 ie m:n =5:10
Using Section Formula :
x= 10(3)+5(0)/10+5
y= 10(5)+5(1)/10+5
x = 30/15= 2
y= 55/15= 11/3
so, (x,y)= (2,11/3)
The coordinate of a point is (2,11/3)
Let , P= (3,5) distance is 5 units from Q and
Let R= (0,1) distance is 10 units from Q.
Let the point be Q(x,y)
Let m and n divide the point in the ratio 5:10 ie m:n =5:10
Using Section Formula :
x= 10(3)+5(0)/10+5
y= 10(5)+5(1)/10+5
x = 30/15= 2
y= 55/15= 11/3
so, (x,y)= (2,11/3)
The coordinate of a point is (2,11/3)
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