find the equation of circle with centre (2, 2) and passes through the point (4, 5)
Answer (1)
26th Mar, 2022
The centre of the circle is given as (h,k)=(2,2)
Since the circle passes through point (4,5), the radius (r) of the circle is the distance between the point (2,2) and (4,5).
r=(2−4)2+(2−5)2=13
Thus, the equation of the circle is(x−h)2+(y−k)2=r2(x−2)2+(y−2)2=13x2−4x+4+y2−4y+4=13x2+y2−4x−4y−5=0
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