Question : Find the least number which when divided separately by 15, 20, 36 and 48 leaves 3 as the remainder in each case.
Option 1: 183
Option 2: 243
Option 3: 483
Option 4: 723
Latest: SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL complete guide
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: 723
Solution : 15 = 3 × 5 20 = 2 × 2 × 5 36 = 3 × 3 × 2 × 2 48 = 2 × 2 × 2 × 2 × 3 LCM = 3 × 3 × 2 × 2 × 2 × 2 × 5 = 720 The remainder will be added to the LCM to get the required number. So, 720 + 3 = 723 Hence, the correct answer is 723.
Candidates can download this ebook to know all about SSC CGL.
Admit Card | Eligibility | Application | Selection Process | Preparation Tips | Result | Answer Key
Question : Find the least number which when divided by 12, 18, 24, and 30 leaves 4 as remainder in each case, but when divided by 7 leaves no remainder.
Question : Let $x$ be the least number which, when divided by 5, 6, 7, and 8, leaves a remainder of 3 in each case, but when divided by 9, leaves no remainder. The sum of the digits of $x$ is:
Question : A number, when divided by 6, leaves a remainder of 3. When the square of the same number is divided by 6, the remainder is:
Question : The least number that must be subtracted from 1294 such that the obtained number when divided by 9, 11, and 13, leaves in each case the same remainder of 6, is:
Question : The largest five-digit number which when divided by 7, 9, and 11, leaves the same remainder as 3 in each case, is:
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile