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Question : Find the value of $\sin (50^{\circ} + A) – \cos (40^{\circ} - A)$.

Option 1: 2

Option 2: 0

Option 3: –1

Option 4: 1


Team Careers360 21st Jan, 2024
Answer (1)
Team Careers360 23rd Jan, 2024

Correct Answer: 0


Solution : We know, $\sin (90^{\circ}-A)=\cos A$
$\sin (50^{\circ} + A) – \cos (40^{\circ} – A)$
$=\sin (50^{\circ} + A) – \cos (90^{\circ}–(50^{\circ} + A))$
$=\sin (50^{\circ} + A) – \sin (50^{\circ} + A)$
$=0$
Hence, the correct answer is 0.

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