Hello there!

Greetings!

Although you haven't completed your question,  I got your question and providing you its solution below :'-

We have ,

a – 3d + a – d + a + d + a + 3d = 360 o (sum of angles of quadrilateral)

4a = 360 o

a = 90 o

According to question,

(a + d) – (a – d) = 10 o

2d = 10 o

d = 5 o

Therefore, (a – 3d) = 90 o – 15 o = 75 o

(a – d) = 90 o – 5 o = 85 o

(a + d) = 90 o + 5 o = 95 o

(a + 3d) = 90 o + 15 o = 105 o

So ,we got all the angles.

Thankyou