Galileo writes that for angles of projection of a projectile at angles (45+alpha) and (45-alpha) the horizontal ranges describe by the pro

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Galileo writes that for angles of projection of a projectile at angles (45+alpha) and (45-alpha) the horizontal ranges describe by the pro

KARSANG YANI 9th Jul, 2019

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NAVEEN MEENA Student Expert 9th Jul, 2019

Dear Karsang,

For complementary angles, range will be same. Therefore,

For angle (45°-θ), R = u2sin(90° - 2θ)/g = u2 cos 2θ/g

For angle 45°+θ), R = u2sin(90° + 2θ)/g = u2 cos 2θ/g

So, the ratio of the projectile is - 1:1

Thus answer is 1:1

All the best

Feel free to ask for any query

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KARSANG YANI

9th Jul, 2019

Thnk you so much

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