graphite pen contain 1.2mg of carbon . calculate no. of C-atoms in it and no. of gram atoms of C in it
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Amount of carbon present in graphite = 1.2 mg = 0.0012 g
No. of carbon atoms present in 12g of carbon = 6.023*10^23
Therefore, No. of carbon atoms present in 1g of carbon = 6.023*10^23/12
Therefore, No. of carbon atoms present in 0.0012g of carbon = 6.023*10^23/12 * 0.0012 = 6.02 * 10^19 atoms (Answer)