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hello mera 90.17 percentile hai aur mai general catagory me aata hu aur general ka cutt off 90.37 hai aur mera rank 105665 hai kya mai advanced ka paper de sakta hu


KumarRai Manohar 13th Sep, 2020
Answer (1)
Anurag Khanna 13th Sep, 2020

Hello Aspirant,

See your eligibility for JEE-Advance is not determined by your rank in JEE-Main instead it is determined by the percentile you scored in your JEE-Main final result. As we know that NTA released the cut-offs for different categories so it is also described below :-

  • Common Rank List (CRL) - 90.3765335
  • GEN-EWS - 70 .2435518
  • Other Backward Classes (OBC-NCL) - 72.8887969
  • Scheduled Caste (SC) - 50.1760245
  • Scheduled Tribe (ST) - 39.0696101
  • PwD - 0.0618524

So in your case you have to secure 90.3765335 percentile to become eligible for JEE-Advance but you does not have that much percentile so you are not eligible for JEE-Advance. For more details kindly refer to the link given below :-

B.Tech/B.Arch Admissions OPEN

Apply to Amrita University B.Tech 2025

https://engineering.careers360.com/articles/jee-main-cutoff/amp

You can use JEE-Main College Predictor to predict your chances of admission in different engineering colleges of India :-

https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer

I hope this information helps you.

Good Luck!!

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