how many electrons must be removed from neutral object of a charge 0.5 ml
Answer (1)
13th Jun, 2020
Hello!!!
Hope you are doing great!!!!
Given Net charge of the neutral object = 0.5 μ C
the charge of the electron = -1.6*10^-19
Net charge in the number of electrons = 0.5*10^-6/-1.6*10^-19
=-3.12*10^-12
The negative sign indicates that the number of electrons to be removed from the object.
Hope it helps you!!!!
Good luck!!!!
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