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how much rank is needed in JEE advanced to get into IIT Kharagpur ,Kanpur, Roorkee ,Goa ,Hyderabad with mechanical engineering and aerospace engineering dual degrees ....


parthibmudi9534 21st Mar, 2020
Answer (1)
Maria Sunny 30th Apr, 2020

Hello,

The closing ranks for various courses varies every year.According to JEE Advanced 2019 the closing ranks for Mechanical Engg for various categories are given below :

IIT Kharagpur :

General - 2259

OBC - 921

EWS - 178

SC - 453

ST - 268

IIT Kanpur :

General  - 2108

OBC - 890

EWS - 181

SC - 576

ST - 342

IIT Roorkee :

General  - 2748

OBC - 1084

EWS - 231

SC - 654

ST - 329

IIT Hyderabad :

General  - 3609

OBC - 1260

EWS - 298

SC - 840

ST - 390

IIT Goa :

General  - 9473

OBC - 3605

EWS - 1052

SC - 1583

ST - 710

The closing ranks for Aerospace Engg for various catogories are given below :

IIT Kharagpur :

General - 3822

OBC - 1651

EWS - 398

SC - 1079

ST - 590

IIT Kanpur :

General  - 3497

OBC - 1717

EWS - 357

SC - 1084

ST - 608

Visit the links below for more details regarding the closing ranks :

https://engineering.careers360.com/articles/iits-cutoff-for-b-tech-mechanical-engineering

https://engineering.careers360.com/articles/iits-cutoff-for-b-tech-aerospace-engineering



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