I got 98.6 percentile in jee paper 2 , can I get nit
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Dear aspirant,
According to NTA Press Release, total 8,69,010 students appeared for JEE-Mains 2020.
98.63 percentile means you can consider your rank to be around 12,000.
It is certainly a very good score, as you have fixed your seat in NITs. There are several options for you to think about with this rank.
You will easily get CSE branch in the following NITs:
NIT Patna
NIT Agartala
NIT Meghalaya
NIT Nagaland
NIT Puducherry
NIT Sikkim
NIT Arunachal Pradesh
NIT Manipur
NIT Mizoram
NIT Silchar
NIT Srinagar
NIT Andhra Pradesh.
Best of luck.
Hello,
Your overall expected rank will be around 1577 and the formula is (100-your total percentile)*112679/100
112679=total number of candidates appeared in JEE Main Paper 2. You have not mentioned your category assuming that you belong to general category you may get seat in MNIT Jaipur, MANIT, Bhopal, NIT Hamirpur, NIT Raipur, NIT Patna, NIT Rourkela, VNIT Nagpur.
Cut off in 2020 may change depending on factors like number of candidates appeared, difficulty of exam, number of seats available etc,
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