I have got 292/300 (phy -100,bio -97,chem-95)in pu board and my cet pcb score is 102/180 (bio -48,phy-26,chem - 28)what will be my approximate bsc ag rank this year
Answer (1)
1st Aug, 2020
Hello aspirant
Cut off marks are calculated by dividing marks secured in each subject by 4 + 50 . Then total marks are divided by number of subjects.
As you have got 48 marks in biology, 48/4 = 12
Your cut off for Biology will be 12+50=62
Physics 26/4=6.5 + 50 = 56.5
For chemistry 28/4 = 7 +50 = 57
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