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I have got 292/300 (phy -100,bio -97,chem-95)in pu board and my cet pcb score is 102/180 (bio -48,phy-26,chem - 28)what will be my approximate bsc ag rank this year


Nikhil Rudra 22nd Jun, 2020
Answer (1)
mjaisinghani62 1st Aug, 2020

Hello aspirant

Cut off marks are calculated by dividing marks secured in each subject by 4 + 50 . Then total marks are divided by number of subjects.

As you have got 48 marks in biology, 48/4 = 12

Your cut off for Biology will be 12+50=62

Physics 26/4=6.5 + 50 = 56.5

For chemistry 28/4 = 7 +50 = 57



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1st Aug, 2020
what will be my approximate ranking
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