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I scored 84.505 percentile in jee mains paper 2 what could be my rank? I belong to obc category


roshani mayur 1st Feb, 2019
Answers (2)
Manikarnika 1st Feb, 2019

Hi Roshani,

This year a total of 1,45,386 aspirant appeared for the JEE B.Arch Examination. Therefore, basing upon the total number of aspirants the formula for calculating your rank would be ([100-your percentile] x 145386)/100. Therefore, approximately your rank will be around 23,190.

Considering this rank, you can yourself look up the allotment list and decide for yourself considering your state and category using the link given below: https://engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning#

To clear any doubts or to know more about JEE B.Arch Results, keep reading Careers 360 using the link given below: Https://engineering.careers360.com/articles/jee-main-paper-2-result

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Apply to Amity University, Noida B.Tech Admissions 2024

Thanks,

dhameerbhatia31_7970609 Student Expert 1st Feb, 2019
Hello Roshani Mayur,



Your Rank is a 22528.



You can use this formula to predict the rank by your percentile.



Rank Formula = (100 - your total score) X 145386 /100.



145386 are the number of students who appeared in the examination.



All the best!



Thanku.











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