Hello Aspirant,

See this is very simple aptitude problem, in which every alphabet is given with code of two times of their position like A is 1st alphabet so A=1*2 and likewise B=2*2 and so on, so KNOT can be written as

K = 11*2 = 22

N = 14*2 =28

O = 15*2 = 30

T = 19*2 = 38

Now sum all above values i.e. 22+28+30+38 = 120. SImilarly for DIYA, it will be written as :

D = 4*2 = 8

I = 9*2 = 18

Y = 25*2 = 50

A = 1*2 = 2

So DIYA will be 8+18+50+2 = 78. So code for DIYA is 78.

I hope this information helps you.

Good Luck!!