if a straight line passing thourgh the point 0(-3,4) is such that its intercepted portion between the coordinate axes is bisected at p , then its equation is
Answer (1)
13th Jan, 2020
Let the equation of required line having intercepts a and b with the axes is x/a+y/b=1.
Now, according to given information,
P
is the mid-point of
AB
Therefore,
P
= (a/2,b/2) => (-3,4). Then (a,b) will be (-6,8).
So, the equation is 4x-3y+24=0. (By substituting in the above equation)
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