Question : If $2x-4\leq \frac{2-x}{3}$ and $2(2x+5)>3x-5$, then $x$ can take which of the following values?
Option 1: –14
Option 2: 3
Option 3: 4
Option 4: 14
Latest: SSC CGL Tier 1 Result 2024 Out | SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL Tier 1 Scorecard 2024 Released | SSC CGL complete guide
Suggested: Month-wise Current Affairs | Upcoming Government Exams
Correct Answer: –14
Solution : Given: $2x-4\leq \frac{2–x}{3}$ and $2(2x+5)>3x-5$ Or, $3×(2x-4)\leq 2-x$ and $(4x+10)>3x-5$ Or, $(6x-12)\leq 2-x$ and $(4x-3x)>-5-10$ Or, $(6x+x)\leq 2+12$ and $(4x-3x)>-15$ Or, $7x\leq14$ and $x>-15$ Or, $x\leq2$ and $x>-15$ Or, $-15<x\leq2$ Amongst all the given values –14 satisfies the above condition. Hence, the correct answer is –14.
Candidates can download this ebook to know all about SSC CGL.
Result | Eligibility | Application | Selection Process | Preparation Tips | Admit Card | Answer Key
Question : If $3x–3<3+\frac{x}{2}$ and $x–2\leq 6+2x$, then $x$ can take which of the following values?
Question : If $2+4x<5-\frac{x}{2}$ and $3x+3>-5-3x$, then $x$ can take which of the following values?
Question : If $2x-6\leq x-3$ and $1+3x<4x+4$, then $x$ can take which of the following values?
Question : If $(x-\frac{1}{3x})=\frac{1}{3}$, then the value of $3(x-\frac{1}{3x})$ is:
Question : If $\frac {x^2+3x+1}{x^2–3x+1}=\frac{1}{2 }$, then the value of $(x+\frac{1}{x})$ is:
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile