Question : If $2+4x<5-\frac{x}{2}$ and $3x+3>-5-3x$, then $x$ can take which of the following values?
Option 1: 1
Option 2: 2
Option 3: –2
Option 4: –1
Latest: SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL complete guide
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: –1
Solution : Given: $2+4x<5-\frac{x}{2}$ and $3x+3>-5-3x$ Or, $2+4x<\frac{10-x}{2}$ and $3x+3x>-5-3$ Or, $2(2+4x)<10-x$ and $6x>-8$ Or, $4+8x<10-x$ and $x>\frac{-8}{6}$ Or, $x+8x<10-4$ and $x>\frac{-4}{3}$ Or, $9x<6$ and $x>-1.33$ Or, $x<\frac{6}{9}$ and $x>-1.33$ Or, $x<0.67$ and $x>-1.33$ Or, $-1.33<x<0.67$ Amongst all the given values –1 satisfies the above condition. Hence, the correct answer is –1.
Candidates can download this ebook to know all about SSC CGL.
Answer Key | Eligibility | Application | Selection Process | Preparation Tips | Result | Admit Card
Question : If $2x-6\leq x-3$ and $1+3x<4x+4$, then $x$ can take which of the following values?
Question : If $2x-4\leq \frac{2-x}{3}$ and $2(2x+5)>3x-5$, then $x$ can take which of the following values?
Question : If $3x–3<3+\frac{x}{2}$ and $x–2\leq 6+2x$, then $x$ can take which of the following values?
Question : If $(x-\frac{1}{3x})=\frac{1}{3}$, then the value of $3(x-\frac{1}{3x})$ is:
Question : If $\frac {x^2+3x+1}{x^2–3x+1}=\frac{1}{2 }$, then the value of $(x+\frac{1}{x})$ is:
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile